What is the answer to solvefor p,8x^2-(4p+2)x+2=0 ?

The answer to solvefor p,8x^2-(4p+2)x+2=0 is p=(4x^2+1-x)/(2x);\quad x\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor p,8x^2-(4p+2)x+2=0

solve for

p, 8 x^{2} - (4 p + 2) x + 2 = 0

p = \frac{4 x ^{2} + 1 - x}{2 x}; x \neq = 0

Solution steps

8 x^{2} - (4 p + 2) x + 2 = 0

Move

8 x^{2}

to the right side

- (4 p + 2) x + 2 = - 8 x^{2}

Move

2

to the right side

- (4 p + 2) x = - 8 x^{2} - 2

Divide both sides by

- x; x \neq = 0

4 p + 2 = - \frac{- 8 x ^{2} - 2}{x}; x \neq = 0

Move

2

to the right side

4 p = - \frac{- 8 x ^{2} - 2}{x} - 2; x \neq = 0

Divide both sides by

4; x \neq = 0

p = \frac{4 x ^{2} + 1 - x}{2 x}; x \neq = 0

x, 3 x + 4 y - 6 = 0

- 10 x + 3 = - 7 x - 3 - 7 x - 3

x, 3 x + 4 y + 5 = 0

\frac{k}{3} + 1 = 4

(7 x - 3) - (1 - 2 x) = 4 - 3 x

What is the answer to solvefor p,8x^2-(4p+2)x+2=0 ?
The answer to solvefor p,8x^2-(4p+2)x+2=0 is p=(4x^2+1-x)/(2x);\quad x\ne 0