What are the solutions to the equation 8x^2-5x-4=0 ?

The solutions to the equation 8x^2-5x-4=0 are x=(5+3sqrt(17))/(16),x=(5-3sqrt(17))/(16)

Find the zeros of 8x^2-5x-4=0

The zeros of 8x^2-5x-4=0 are x=(5+3sqrt(17))/(16),x=(5-3sqrt(17))/(16)

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8 x^{2} - 5 x - 4 = 0

x = \frac{5 + 3 17}{16}, x = \frac{5 - 3 17}{16}

Solution steps

8 x^{2} - 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 8 ( - 4 )}{2 \cdot 8}

(- 5)^{2} - 4 \cdot 8 (- 4) = 317

x_{1, 2} = \frac{- ( - 5 ) \pm 3 17}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 17}{2 \cdot 8}, x_{2} = \frac{- ( - 5 ) - 3 17}{2 \cdot 8}

x = \frac{- ( - 5 ) + 3 17}{2 \cdot 8} : \frac{5 + 3 17}{16}

x = \frac{- ( - 5 ) - 3 17}{2 \cdot 8} : \frac{5 - 3 17}{16}

The solutions to the quadratic equation are:

x = \frac{5 + 3 17}{16}, x = \frac{5 - 3 17}{16}

0.6

9 v + 7 \leq 10 v - 4

\frac{- 2}{1 + 3 i}

e^{0.06} - 1

x^{3} - 49 x \geq 0

What are the solutions to the equation 8x^2-5x-4=0 ?
The solutions to the equation 8x^2-5x-4=0 are x=(5+3sqrt(17))/(16),x=(5-3sqrt(17))/(16)
Find the zeros of 8x^2-5x-4=0
The zeros of 8x^2-5x-4=0 are x=(5+3sqrt(17))/(16),x=(5-3sqrt(17))/(16)