What are the solutions to the equation y^2-2y-10=0 ?

The solutions to the equation y^2-2y-10=0 are y=1+sqrt(11),y=1-sqrt(11)

Find the zeros of y^2-2y-10=0

The zeros of y^2-2y-10=0 are y=1+sqrt(11),y=1-sqrt(11)

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y^{2} - 2 y - 10 = 0

y = 1 + 11, y = 1 - 11

Decimal Notation

y = 4.31662 \dots, y = - 2.31662 \dots

Solution steps

y^{2} - 2 y - 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 10) = 211

y_{1, 2} = \frac{- ( - 2 ) \pm 2 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2 11}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2 11}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2 11}{2 \cdot 1} : 1 + 11

y = \frac{- ( - 2 ) - 2 11}{2 \cdot 1} : 1 - 11

The solutions to the quadratic equation are:

y = 1 + 11, y = 1 - 11

∣ x - 1 ∣ = 1 - x

f = 6^{2}

3 2^{\frac{5}{2}}

8 v - 24

y^{2} = 20

What are the solutions to the equation y^2-2y-10=0 ?
The solutions to the equation y^2-2y-10=0 are y=1+sqrt(11),y=1-sqrt(11)
Find the zeros of y^2-2y-10=0
The zeros of y^2-2y-10=0 are y=1+sqrt(11),y=1-sqrt(11)