What are the solutions to the equation (2x-4)^2=16 ?

The solutions to the equation (2x-4)^2=16 are x=4,x=0

Find the zeros of (2x-4)^2=16

The zeros of (2x-4)^2=16 are x=4,x=0

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(2 x - 4)^{2} = 16

x = 4, x = 0

Solution steps

(2 x - 4)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 4 = 16 : x = 4

Solve

2 x - 4 = - 16 : x = 0

The solutions to the quadratic equation are:

x = 4, x = 0

\frac{x + 8}{10} = 0

x - 6 = 4

1 \leq - 2 x + 9 < 8

3.4 < 0.4 (a + 12)

- 18 + 42 x

What are the solutions to the equation (2x-4)^2=16 ?
The solutions to the equation (2x-4)^2=16 are x=4,x=0
Find the zeros of (2x-4)^2=16
The zeros of (2x-4)^2=16 are x=4,x=0