What is the answer to (x+1)/2+(x-2)/4 =(2x-1)/8 ?

The answer to (x+1)/2+(x-2)/4 =(2x-1)/8 is x=-1/4

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(x+1)/2+(x-2)/4 =(2x-1)/8

\frac{x + 1}{2} + \frac{x - 2}{4} = \frac{2 x - 1}{8}

x = - \frac{1}{4}

Decimal Notation

x = - 0.25

Solution steps

\frac{x + 1}{2} + \frac{x - 2}{4} = \frac{2 x - 1}{8}

Multiply by LCM

4 (x + 1) + 2 (x - 2) = 2 x - 1

Expand

4 (x + 1) + 2 (x - 2) : 6 x

6 x = 2 x - 1

Move

2 x

to the left side

4 x = - 1

Divide both sides by

4

x = - \frac{1}{4}

- \frac{3}{2} m = \frac{15}{16}

- 5 w + 1 = 2

5 x - 465 = 0

\frac{1}{10} x + \frac{1}{4} x = 21

a, a - b = 2

What is the answer to (x+1)/2+(x-2)/4 =(2x-1)/8 ?
The answer to (x+1)/2+(x-2)/4 =(2x-1)/8 is x=-1/4
Solve for x: (x+1)/2+(x-2)/4 =(2x-1)/8
The solution is x=-1/4