What is the answer to 2/9 (0^3+2)^{3/2}+C=-1/(sqrt(3)) ?

The answer to 2/9 (0^3+2)^{3/2}+C=-1/(sqrt(3)) is C=-1/(sqrt(3))-(4*2^{1/2})/9

Solve for C: 2/9 (0^3+2)^{3/2}+C=-1/(sqrt(3))

The solution is C=-1/(sqrt(3))-(4*2^{1/2})/9

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\frac{2}{9} (0^{3} + 2)^{\frac{3}{2}} + C = - \frac{1}{3}

C = - \frac{1}{3} - \frac{4 \cdot 2 ^{\frac{1}{2}}}{9}

Decimal Notation

C = - 1.20588 \dots

Solution steps

\frac{2}{9} (0^{3} + 2)^{\frac{3}{2}} + C = - \frac{1}{3}

Simplify

\frac{2}{9} (0^{3} + 2)^{\frac{3}{2}} + C : \frac{4 \cdot 2 ^{\frac{1}{2}}}{9} + C

\frac{4 \cdot 2 ^{\frac{1}{2}}}{9} + C = - \frac{1}{3}

Move

\frac{4 \cdot 2 ^{\frac{1}{2}}}{9}

to the right side

C = - \frac{1}{3} - \frac{4 \cdot 2 ^{\frac{1}{2}}}{9}

5 - 2 x = - 4 x + 9

\frac{1}{8} (5 y + 64) = \frac{1}{4} (20 + 2 y)

b - 3 = - 4

x, 2 y = 5 x + 4

- 2 (x - 3) = 30

What is the answer to 2/9 (0^3+2)^{3/2}+C=-1/(sqrt(3)) ?
The answer to 2/9 (0^3+2)^{3/2}+C=-1/(sqrt(3)) is C=-1/(sqrt(3))-(4*2^{1/2})/9
Solve for C: 2/9 (0^3+2)^{3/2}+C=-1/(sqrt(3))
The solution is C=-1/(sqrt(3))-(4*2^{1/2})/9