What is the answer to (1-t)l^{1/k}=1 ?

The answer to (1-t)l^{1/k}=1 is t=-(1-l^{1/k})/(l^{1/k)};\quad t^{1/k}\ne 0

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(1-t)l^{1/k}=1

(1 - t) l^{\frac{1}{k}} = 1

t = - \frac{1 - l ^{\frac{1}{k}}}{l ^{\frac{1}{k}}}; t^{\frac{1}{k}} \neq = 0

Solution steps

(1 - t) l^{\frac{1}{k}} = 1

Divide both sides by

l^{\frac{1}{k}}; t^{\frac{1}{k}} \neq = 0

1 - t = \frac{1}{l ^{\frac{1}{k}}}; t^{\frac{1}{k}} \neq = 0

Move

1

to the right side

- t = \frac{1}{l ^{\frac{1}{k}}} - 1; t^{\frac{1}{k}} \neq = 0

Divide both sides by

- 1; t^{\frac{1}{k}} \neq = 0

t = - \frac{1 - l ^{\frac{1}{k}}}{l ^{\frac{1}{k}}}; t^{\frac{1}{k}} \neq = 0

2 x - 7 = 10

7 x - 9 = 4 x

5 (x - 3) + 1 = 2 (x + 7) - 4

A, S A = 2 π r^{2} + 2 π r h

0.75 j - 18 = - 3

What is the answer to (1-t)l^{1/k}=1 ?
The answer to (1-t)l^{1/k}=1 is t=-(1-l^{1/k})/(l^{1/k)};\quad t^{1/k}\ne 0