What is the answer to solvefor A,2s-11=A(s+4)+B(s-6) ?

The answer to solvefor A,2s-11=A(s+4)+B(s-6) is A=(2s-11-B(s-6))/(s+4);\quad s\ne-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor A,2s-11=A(s+4)+B(s-6)

solve for

A, 2 s - 11 = A (s + 4) + B (s - 6)

A = \frac{2 s - 11 - B ( s - 6 )}{s + 4}; s \neq = - 4

Solution steps

2 s - 11 = A (s + 4) + B (s - 6)

Switch sides

A (s + 4) + B (s - 6) = 2 s - 11

Move

B (s - 6)

to the right side

A (s + 4) = 2 s - 11 - B (s - 6)

Divide both sides by

s + 4; s \neq = - 4

A = \frac{2 s - 11 - B ( s - 6 )}{s + 4}; s \neq = - 4

9 (n - 4) = 54

0.6 g + 11 = 5

- x + 7 = - 6 x - 13 - 6 x - 13

y = lo g_{5} (25)

9 + k = 18

What is the answer to solvefor A,2s-11=A(s+4)+B(s-6) ?
The answer to solvefor A,2s-11=A(s+4)+B(s-6) is A=(2s-11-B(s-6))/(s+4);\quad s\ne-4