What is the answer to (x-1)(x+3)=(x+2)(x-3)+1 ?

The answer to (x-1)(x+3)=(x+2)(x-3)+1 is x=-2/3

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(x-1)(x+3)=(x+2)(x-3)+1

(x - 1) (x + 3) = (x + 2) (x - 3) + 1

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

(x - 1) (x + 3) = (x + 2) (x - 3) + 1

Expand

(x - 1) (x + 3) : x^{2} + 2 x - 3

Expand

(x + 2) (x - 3) + 1 : x^{2} - x - 5

x^{2} + 2 x - 3 = x^{2} - x - 5

Move

3

to the right side

x^{2} + 2 x = x^{2} - x - 2

Subtract

x^{2} - x

from both sides

x^{2} + 2 x - (x^{2} - x) = x^{2} - x - 2 - (x^{2} - x)

Simplify

3 x = - 2

Divide both sides by

3

x = - \frac{2}{3}

1 \leq \frac{3 x ^{2} - 7 x + 8}{x ^{2} + 1} \leq 2

v^{2} - 6 v + 8

\frac{x}{- 20} = 4.5

(\frac{2}{x ^{3}})^{2}

4 x^{2} + 2 x - 12

What is the answer to (x-1)(x+3)=(x+2)(x-3)+1 ?
The answer to (x-1)(x+3)=(x+2)(x-3)+1 is x=-2/3
Solve for x: (x-1)(x+3)=(x+2)(x-3)+1
The solution is x=-2/3