What are the solutions to the equation -x^2-5x+12=0 ?

The solutions to the equation -x^2-5x+12=0 are x=-(5+sqrt(73))/2 ,x=(sqrt(73)-5)/2

Find the zeros of -x^2-5x+12=0

The zeros of -x^2-5x+12=0 are x=-(5+sqrt(73))/2 ,x=(sqrt(73)-5)/2

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- x^{2} - 5 x + 12 = 0

x = - \frac{5 + 73}{2}, x = \frac{73 - 5}{2}

Decimal Notation

x = - 6.77200 \dots, x = 1.77200 \dots

Solution steps

- x^{2} - 5 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) \cdot 12}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) \cdot 12 = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 ( - 1 )}, x_{2} = \frac{- ( - 5 ) - 73}{2 ( - 1 )}

x = \frac{- ( - 5 ) + 73}{2 ( - 1 )} : - \frac{5 + 73}{2}

x = \frac{- ( - 5 ) - 73}{2 ( - 1 )} : \frac{73 - 5}{2}

The solutions to the quadratic equation are:

x = - \frac{5 + 73}{2}, x = \frac{73 - 5}{2}

- 10 z = \frac{2}{3}

3 x^{2} - 9 y

12 - 8 x \geq 10 x - 6

∣ 3 x - 2 ∣ = ∣ x + 2 ∣

\frac{x}{5} + 2 x = \frac{16}{7} - x

What are the solutions to the equation -x^2-5x+12=0 ?
The solutions to the equation -x^2-5x+12=0 are x=-(5+sqrt(73))/2 ,x=(sqrt(73)-5)/2
Find the zeros of -x^2-5x+12=0
The zeros of -x^2-5x+12=0 are x=-(5+sqrt(73))/2 ,x=(sqrt(73)-5)/2