What is the answer to solvefor x,y-(3y+2)/7 =(x+18)/(10) ?

The answer to solvefor x,y-(3y+2)/7 =(x+18)/(10) is x=10y-(10(3y+2))/7-18

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solvefor x,y-(3y+2)/7 =(x+18)/(10)

solve for

x, y - \frac{3 y + 2}{7} = \frac{x + 18}{10}

x = 10 y - \frac{10 ( 3 y + 2 )}{7} - 18

Solution steps

y - \frac{3 y + 2}{7} = \frac{x + 18}{10}

Switch sides

\frac{x + 18}{10} = y - \frac{3 y + 2}{7}

Multiply both sides by

10

x + 18 = 10 y - \frac{10 ( 3 y + 2 )}{7}

Move

18

to the right side

x = 10 y - \frac{10 ( 3 y + 2 )}{7} - 18

\frac{x}{8} + 3 = 0, x

\frac{1}{2} (6 a - 8) = 4 a + 30

E = \frac{20 ! + 21 ! + 22 !}{20 ! + 21 !}

x, 2 y - x - 2 = 0

y, 3 x + 1 + 2 y = 2 y + 2 - 3 x

What is the answer to solvefor x,y-(3y+2)/7 =(x+18)/(10) ?
The answer to solvefor x,y-(3y+2)/7 =(x+18)/(10) is x=10y-(10(3y+2))/7-18