What are the solutions to the equation x^2-12x+11=0 ?

The solutions to the equation x^2-12x+11=0 are x=11,x=1

Find the zeros of x^2-12x+11=0

The zeros of x^2-12x+11=0 are x=11,x=1

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x^{2} - 12 x + 11 = 0

x = 11, x = 1

Solution steps

x^{2} - 12 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 11 = 10

x_{1, 2} = \frac{- ( - 12 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 10}{2 \cdot 1}

x = \frac{- ( - 12 ) + 10}{2 \cdot 1} : 11

x = \frac{- ( - 12 ) - 10}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 11, x = 1

3 x = 4 (x - 9)

12 \cdot 8

lo g_{2} (6) - lo g_{2} (15) + lo g_{2} (20)

9 t^{2} + 24 t

2 (x - 1) (x + 4) + (x - 1)^{2} > 0

What are the solutions to the equation x^2-12x+11=0 ?
The solutions to the equation x^2-12x+11=0 are x=11,x=1
Find the zeros of x^2-12x+11=0
The zeros of x^2-12x+11=0 are x=11,x=1