What is the answer to (x+3)^2=(x-2)^2+15 ?

The answer to (x+3)^2=(x-2)^2+15 is x=1

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(x+3)^2=(x-2)^2+15

(x + 3)^{2} = (x - 2)^{2} + 15

x = 1

Solution steps

(x + 3)^{2} = (x - 2)^{2} + 15

Expand

(x + 3)^{2} : x^{2} + 6 x + 9

Expand

(x - 2)^{2} + 15 : x^{2} - 4 x + 19

x^{2} + 6 x + 9 = x^{2} - 4 x + 19

Move

9

to the right side

x^{2} + 6 x = x^{2} - 4 x + 10

Subtract

x^{2} - 4 x

from both sides

x^{2} + 6 x - (x^{2} - 4 x) = x^{2} - 4 x + 10 - (x^{2} - 4 x)

Simplify

10 x = 10

Divide both sides by

10

x = 1

2 k - 3 (k + 5) = 2 k - (3 k - 2) - (3 k - 7)

7 x + 15 a x - 110 + \frac{185}{9} a x = 18 x - 5 a + \frac{12}{57} a

\frac{1 + r}{- 1.5} = 9

x, - 3 x - 6 y = 0

y = lo g_{4} (64)

What is the answer to (x+3)^2=(x-2)^2+15 ?
The answer to (x+3)^2=(x-2)^2+15 is x=1
Solve for x: (x+3)^2=(x-2)^2+15
The solution is x=1