What is the answer to (2t+5)/6+(t-4)/9+(3t+7)/2 = 1/3 ?

The answer to (2t+5)/6+(t-4)/9+(3t+7)/2 = 1/3 is t=-64/35

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(2t+5)/6+(t-4)/9+(3t+7)/2 = 1/3

\frac{2 t + 5}{6} + \frac{t - 4}{9} + \frac{3 t + 7}{2} = \frac{1}{3}

t = - \frac{64}{35}

Decimal Notation

t = - 1.82857 \dots

Solution steps

\frac{2 t + 5}{6} + \frac{t - 4}{9} + \frac{3 t + 7}{2} = \frac{1}{3}

Multiply by LCM

3 (2 t + 5) + 2 (t - 4) + 9 (3 t + 7) = 6

Expand

3 (2 t + 5) + 2 (t - 4) + 9 (3 t + 7) : 35 t + 70

35 t + 70 = 6

Move

70

to the right side

35 t = - 64

Divide both sides by

35

t = - \frac{64}{35}

x, 4 x - 9 y = - 9

\frac{2 x}{5} - \frac{3}{2} = - 1 - \frac{x}{10}

x, z = x + i y

x, 2 x - 1 = 0

\frac{2 x}{15} = \frac{4}{5} - 2 x

What is the answer to (2t+5)/6+(t-4)/9+(3t+7)/2 = 1/3 ?
The answer to (2t+5)/6+(t-4)/9+(3t+7)/2 = 1/3 is t=-64/35
Solve for t: (2t+5)/6+(t-4)/9+(3t+7)/2 = 1/3
The solution is t=-64/35