What is the answer to (x+2)(x-2)-1=(x+2)^2 ?

The answer to (x+2)(x-2)-1=(x+2)^2 is x=-9/4

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(x+2)(x-2)-1=(x+2)^2

(x + 2) (x - 2) - 1 = (x + 2)^{2}

x = - \frac{9}{4}

Decimal Notation

x = - 2.25

Solution steps

(x + 2) (x - 2) - 1 = (x + 2)^{2}

Expand

(x + 2) (x - 2) - 1 : x^{2} - 5

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

x^{2} - 5 = x^{2} + 4 x + 4

Move

5

to the right side

x^{2} = x^{2} + 4 x + 9

Subtract

x^{2} + 4 x

from both sides

x^{2} - (x^{2} + 4 x) = x^{2} + 4 x + 9 - (x^{2} + 4 x)

Simplify

- 4 x = 9

Divide both sides by

- 4

x = - \frac{9}{4}

a, (a + b) (2 a + 1) = a (2 a + 2 b + 1)

y, x = \frac{y - z}{2}

- 6 x + 3 = 45

x, - 2 x + 5 y = 15

6 n + 8 = 4 n - 9

What is the answer to (x+2)(x-2)-1=(x+2)^2 ?
The answer to (x+2)(x-2)-1=(x+2)^2 is x=-9/4
Solve for x: (x+2)(x-2)-1=(x+2)^2
The solution is x=-9/4