What is the answer to solvefor x,(2y+1)^3-24x=-3 ?

The answer to solvefor x,(2y+1)^3-24x=-3 is x=(4y^3+6y^2+3y+2)/(12)

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solvefor x,(2y+1)^3-24x=-3

solve for

x, (2 y + 1)^{3} - 24 x = - 3

x = \frac{4 y ^{3} + 6 y ^{2} + 3 y + 2}{12}

Solution steps

(2 y + 1)^{3} - 24 x = - 3

Move

(2 y + 1)^{3}

to the right side

- 24 x = - 8 y^{3} - 12 y^{2} - 6 y - 4

Divide both sides by

- 24

x = \frac{4 y ^{3} + 6 y ^{2} + 3 y + 2}{12}

x, 3 x^{2} + 3 y^{2} + 3 z^{2} + 2 x y - 2 yz + 2 x z = 0

a, 2 a + b = 9

5 = \frac{z}{- 4} - 3

y = 4 lo g_{10} (0 + 10) - 2

x, T = (x + y^{2} x y - z)

What is the answer to solvefor x,(2y+1)^3-24x=-3 ?
The answer to solvefor x,(2y+1)^3-24x=-3 is x=(4y^3+6y^2+3y+2)/(12)