What is the answer to (2x-1)^2-(2x+5)(2x-5)=18 ?

The answer to (2x-1)^2-(2x+5)(2x-5)=18 is x=2

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(2x-1)^2-(2x+5)(2x-5)=18

(2 x - 1)^{2} - (2 x + 5) (2 x - 5) = 18

x = 2

Solution steps

(2 x - 1)^{2} - (2 x + 5) (2 x - 5) = 18

Expand

(2 x - 1)^{2} - (2 x + 5) (2 x - 5) : - 4 x + 26

- 4 x + 26 = 18

Move

26

to the right side

- 4 x = - 8

Divide both sides by

- 4

x = 2

15 = 12 u

5 x = 3 x + 2

3 x + 2 x = 180

6 x + 3 = 4 x + 9

x, x + 2 = \frac{1}{y}

What is the answer to (2x-1)^2-(2x+5)(2x-5)=18 ?
The answer to (2x-1)^2-(2x+5)(2x-5)=18 is x=2
Solve for x: (2x-1)^2-(2x+5)(2x-5)=18
The solution is x=2