What is the answer to x/4+(x+1)/3+(x-2)/6 =x-3 ?

The answer to x/4+(x+1)/3+(x-2)/6 =x-3 is x=12

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x/4+(x+1)/3+(x-2)/6 =x-3

\frac{x}{4} + \frac{x + 1}{3} + \frac{x - 2}{6} = x - 3

x = 12

Solution steps

\frac{x}{4} + \frac{x + 1}{3} + \frac{x - 2}{6} = x - 3

Multiply by LCM

3 x + 4 (x + 1) + 2 (x - 2) = 12 x - 36

Expand

3 x + 4 (x + 1) + 2 (x - 2) : 9 x

9 x = 12 x - 36

Move

12 x

to the left side

- 3 x = - 36

Divide both sides by

- 3

x = 12

+ \frac{1}{3} = \frac{3}{4}

- 24 + 5 n = 2 n + 24

- 31 = - 7 v + 2 (v + 7)

a, an = 2 n - 1

8 + 4 = 2 (x - 1)

What is the answer to x/4+(x+1)/3+(x-2)/6 =x-3 ?
The answer to x/4+(x+1)/3+(x-2)/6 =x-3 is x=12
Solve for x: x/4+(x+1)/3+(x-2)/6 =x-3
The solution is x=12