What is the answer to 3(2a-x)+ax=a^2+25 ?

The answer to 3(2a-x)+ax=a^2+25 is x=(a^2+25-6a)/(-3+a);\quad a\ne 3

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3(2a-x)+ax=a^2+25

3 (2 a - x) + a x = a^{2} + 25

x = \frac{a ^{2} + 25 - 6 a}{- 3 + a}; a \neq = 3

Solution steps

3 (2 a - x) + a x = a^{2} + 25

Expand

3 (2 a - x) : 6 a - 3 x

6 a - 3 x + a x = a^{2} + 25

Move

6 a

to the right side

- 3 x + a x = a^{2} + 25 - 6 a

Factor

- 3 x + a x : x (- 3 + a)

x (- 3 + a) = a^{2} + 25 - 6 a

Divide both sides by

- 3 + a; a \neq = 3

x = \frac{a ^{2} + 25 - 6 a}{- 3 + a}; a \neq = 3

2 (x - 1) - 3 = 5 x

10 = 15 - 5 x

- 7 (8 + 5 y) + 8 y = 25

2 x + 7 = 6 x - 7

x, 8 x - 10 y = 20

What is the answer to 3(2a-x)+ax=a^2+25 ?
The answer to 3(2a-x)+ax=a^2+25 is x=(a^2+25-6a)/(-3+a);\quad a\ne 3