What are the solutions to the equation 3(x-4)^2=15 ?

The solutions to the equation 3(x-4)^2=15 are x=sqrt(5)+4,x=-sqrt(5)+4

Find the zeros of 3(x-4)^2=15

The zeros of 3(x-4)^2=15 are x=sqrt(5)+4,x=-sqrt(5)+4

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3 (x - 4)^{2} = 15

x = 5 + 4, x = - 5 + 4

Decimal Notation

x = 6.23606 \dots, x = 1.76393 \dots

Solution steps

3 (x - 4)^{2} = 15

Divide both sides by

3

(x - 4)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 5 : x = 5 + 4

Solve

x - 4 = - 5 : x = - 5 + 4

The solutions to the quadratic equation are:

x = 5 + 4, x = - 5 + 4

4 x + 7 \leq 8 x + 5

83.52

\frac{- 2}{2}

\frac{π}{6} + \frac{π}{6}

∣ x + 10 ∣ + 1 = 7

What are the solutions to the equation 3(x-4)^2=15 ?
The solutions to the equation 3(x-4)^2=15 are x=sqrt(5)+4,x=-sqrt(5)+4
Find the zeros of 3(x-4)^2=15
The zeros of 3(x-4)^2=15 are x=sqrt(5)+4,x=-sqrt(5)+4