What are the solutions to the equation 3X^2+4X-2=0 ?

The solutions to the equation 3X^2+4X-2=0 are X=(-2+sqrt(10))/3 ,X=-(2+sqrt(10))/3

Find the zeros of 3X^2+4X-2=0

The zeros of 3X^2+4X-2=0 are X=(-2+sqrt(10))/3 ,X=-(2+sqrt(10))/3

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3 X^{2} + 4 X - 2 = 0

X = \frac{- 2 + 10}{3}, X = - \frac{2 + 10}{3}

Decimal Notation

X = 0.38742 \dots, X = - 1.72075 \dots

Solution steps

3 X^{2} + 4 X - 2 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 2) = 210

X_{1, 2} = \frac{- 4 \pm 2 10}{2 \cdot 3}

Separate the solutions

X_{1} = \frac{- 4 + 2 10}{2 \cdot 3}, X_{2} = \frac{- 4 - 2 10}{2 \cdot 3}

X = \frac{- 4 + 2 10}{2 \cdot 3} : \frac{- 2 + 10}{3}

X = \frac{- 4 - 2 10}{2 \cdot 3} : - \frac{2 + 10}{3}

The solutions to the quadratic equation are:

X = \frac{- 2 + 10}{3}, X = - \frac{2 + 10}{3}

\frac{y}{2} + \frac{y}{7} = 9

- 50 u^{2} - 22 = 0

81

80 \geq - 8 (w - 8)

\frac{x}{4} - \frac{x}{5} = 1

What are the solutions to the equation 3X^2+4X-2=0 ?
The solutions to the equation 3X^2+4X-2=0 are X=(-2+sqrt(10))/3 ,X=-(2+sqrt(10))/3
Find the zeros of 3X^2+4X-2=0
The zeros of 3X^2+4X-2=0 are X=(-2+sqrt(10))/3 ,X=-(2+sqrt(10))/3