What is the answer to (3y-6)/9 =(4-2y)/(-3) ?

The answer to (3y-6)/9 =(4-2y)/(-3) is y=2

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(3y-6)/9 =(4-2y)/(-3)

\frac{3 y - 6}{9} = \frac{4 - 2 y}{- 3}

y = 2

Solution steps

\frac{3 y - 6}{9} = \frac{4 - 2 y}{- 3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(3 y - 6) (- 3) = 9 (4 - 2 y)

Simplify

- 3 (3 y - 6) = 9 (4 - 2 y)

Expand

- 3 (3 y - 6) : - 9 y + 18

Expand

9 (4 - 2 y) : 36 - 18 y

- 9 y + 18 = 36 - 18 y

Move

18

to the right side

- 9 y = - 18 y + 18

Move

18 y

to the left side

9 y = 18

Divide both sides by

9

y = 2

y = 500 (3)^{\frac{40}{15}}

\frac{3 x}{5} - \frac{4 x}{15} = 7 - \frac{2 x - 2}{2}

2 x - 4 = x + 2

lo g_{5} (125) = t

lo g_{5} (125) = m

What is the answer to (3y-6)/9 =(4-2y)/(-3) ?
The answer to (3y-6)/9 =(4-2y)/(-3) is y=2
Solve for y: (3y-6)/9 =(4-2y)/(-3)
The solution is y=2