What are the solutions to the equation 2=m^2+4 ?

The solutions to the equation 2=m^2+4 are m=sqrt(2)i,m=-sqrt(2)i

Find the zeros of 2=m^2+4

The zeros of 2=m^2+4 are m=sqrt(2)i,m=-sqrt(2)i

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2 = m^{2} + 4

m = 2 i, m = - 2 i

Solution steps

2 = m^{2} + 4

Switch sides

m^{2} + 4 = 2

Move

4

to the right side

m^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = - 2, m = - - 2

- 2 = 2 i

- - 2 = - 2 i

m = 2 i, m = - 2 i

q^{4} + 5 q^{3} + 8 q + 40

4 x^{2} + 15 x^{3} + 4 x y - 2 x^{3}

- 10 (y - 4) + 3 y = 5

((a + b)^{2})^{2}

x^{2} + 16 x + 63 = 0

What are the solutions to the equation 2=m^2+4 ?
The solutions to the equation 2=m^2+4 are m=sqrt(2)i,m=-sqrt(2)i
Find the zeros of 2=m^2+4
The zeros of 2=m^2+4 are m=sqrt(2)i,m=-sqrt(2)i