What are the solutions to the equation 8x^2=-26x ?

The solutions to the equation 8x^2=-26x are x=0,x=-13/4

Find the zeros of 8x^2=-26x

The zeros of 8x^2=-26x are x=0,x=-13/4

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8 x^{2} = - 26 x

x = 0, x = - \frac{13}{4}

Decimal Notation

x = 0, x = - 3.25

Solution steps

8 x^{2} = - 26 x

Move

26 x

to the left side

8 x^{2} + 26 x = 0

Factor

8 x^{2} + 26 x : 2 x (4 x + 13)

2 x (4 x + 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x + 13 = 0

Solve

4 x + 13 = 0 : x = - \frac{13}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{13}{4}

x^{2} + (x + 7)^{2} = (2 x - 7)^{2}

3 x^{2} + 13 x + 4

8 x \geq - 16

\frac{- 9}{- 3}

y - 24 = - 7

What are the solutions to the equation 8x^2=-26x ?
The solutions to the equation 8x^2=-26x are x=0,x=-13/4
Find the zeros of 8x^2=-26x
The zeros of 8x^2=-26x are x=0,x=-13/4