What is the answer to solvefor a,f=(ax^3+3)/(bx^2-2) ?

The answer to solvefor a,f=(ax^3+3)/(bx^2-2) is a=(f(bx^2-2)-3)/(x^3);\quad bx^2-2\ne 0,x\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,f=(ax^3+3)/(bx^2-2)

solve for

a, f = \frac{a x ^{3} + 3}{b x ^{2} - 2}

a = \frac{f ( b x ^{2} - 2 ) - 3}{x ^{3}}; b x^{2} - 2 \neq = 0, x \neq = 0

Solution steps

f = \frac{a x ^{3} + 3}{b x ^{2} - 2}

Switch sides

\frac{a x ^{3} + 3}{b x ^{2} - 2} = f

Multiply both sides by

b x^{2} - 2

a x^{3} + 3 = f (b x^{2} - 2); b x^{2} - 2 \neq = 0

Move

3

to the right side

a x^{3} = f (b x^{2} - 2) - 3; b x^{2} - 2 \neq = 0

Divide both sides by

x^{3}; b x^{2} - 2 \neq = 0, x \neq = 0

a = \frac{f ( b x ^{2} - 2 ) - 3}{x ^{3}}; b x^{2} - 2 \neq = 0, x \neq = 0

- 17 + 12 n = 18 - 16 + 11 n

3 x - 9 = 3 (x - 3)

x, y + 5 = 7 (x - 8)

x, 5 x + 2 y = - 9

x, 5 x + 2 y = 13

What is the answer to solvefor a,f=(ax^3+3)/(bx^2-2) ?
The answer to solvefor a,f=(ax^3+3)/(bx^2-2) is a=(f(bx^2-2)-3)/(x^3);\quad bx^2-2\ne 0,x\ne 0