What are the solutions to the equation 3w^2+w=-3 ?

The solutions to the equation 3w^2+w=-3 are w=-1/6+i(sqrt(35))/6 ,w=-1/6-i(sqrt(35))/6

Find the zeros of 3w^2+w=-3

The zeros of 3w^2+w=-3 are w=-1/6+i(sqrt(35))/6 ,w=-1/6-i(sqrt(35))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 w^{2} + w = - 3

w = - \frac{1}{6} + i \frac{35}{6}, w = - \frac{1}{6} - i \frac{35}{6}

Solution steps

3 w^{2} + w = - 3

Move

3

to the left side

3 w^{2} + w + 3 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

Simplify

1^{2} - 4 \cdot 3 \cdot 3 : 35 i

w_{1, 2} = \frac{- 1 \pm 35 i}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- 1 + 35 i}{2 \cdot 3}, w_{2} = \frac{- 1 - 35 i}{2 \cdot 3}

w = \frac{- 1 + 35 i}{2 \cdot 3} : - \frac{1}{6} + i \frac{35}{6}

w = \frac{- 1 - 35 i}{2 \cdot 3} : - \frac{1}{6} - i \frac{35}{6}

The solutions to the quadratic equation are:

w = - \frac{1}{6} + i \frac{35}{6}, w = - \frac{1}{6} - i \frac{35}{6}

- 12 m - 4 n

1 - x < 7 + x or 4 x + 3 > x

3 2^{- \frac{8}{5}}

∣ 6 b + 5 ∣ - 4 = 9

5 (2 + w) - w = 10 + 4 (w + 1)

What are the solutions to the equation 3w^2+w=-3 ?
The solutions to the equation 3w^2+w=-3 are w=-1/6+i(sqrt(35))/6 ,w=-1/6-i(sqrt(35))/6
Find the zeros of 3w^2+w=-3
The zeros of 3w^2+w=-3 are w=-1/6+i(sqrt(35))/6 ,w=-1/6-i(sqrt(35))/6