What is the answer to (x-8)^2-7(x-7)(x+7)-8x=(x+8)^2-x(7x-1) ?

The answer to (x-8)^2-7(x-7)(x+7)-8x=(x+8)^2-x(7x-1) is x= 343/41

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(x-8)^2-7(x-7)(x+7)-8x=(x+8)^2-x(7x-1)

(x - 8)^{2} - 7 (x - 7) (x + 7) - 8 x = (x + 8)^{2} - x (7 x - 1)

x = \frac{343}{41}

Decimal Notation

x = 8.36585 \dots

Solution steps

(x - 8)^{2} - 7 (x - 7) (x + 7) - 8 x = (x + 8)^{2} - x (7 x - 1)

Expand

(x - 8)^{2} - 7 (x - 7) (x + 7) - 8 x : - 6 x^{2} - 24 x + 407

Expand

(x + 8)^{2} - x (7 x - 1) : - 6 x^{2} + 17 x + 64

- 6 x^{2} - 24 x + 407 = - 6 x^{2} + 17 x + 64

Move

407

to the right side

- 6 x^{2} - 24 x = - 6 x^{2} + 17 x - 343

Subtract

- 6 x^{2} + 17 x

from both sides

- 6 x^{2} - 24 x - (- 6 x^{2} + 17 x) = - 6 x^{2} + 17 x - 343 - (- 6 x^{2} + 17 x)

Simplify

- 41 x = - 343

Divide both sides by

- 41

x = \frac{343}{41}

x, 3 x + y + z = 2

x, 3 x - 4 y = - 2

y, x = 2 y + 8

x = 17 - 2

3 (k - 5) = - 16

What is the answer to (x-8)^2-7(x-7)(x+7)-8x=(x+8)^2-x(7x-1) ?
The answer to (x-8)^2-7(x-7)(x+7)-8x=(x+8)^2-x(7x-1) is x= 343/41
Solve for x: (x-8)^2-7(x-7)(x+7)-8x=(x+8)^2-x(7x-1)
The solution is x= 343/41