What is the answer to (x^2+5x-6)^0=1 ?

The answer to (x^2+5x-6)^0=1 is True for all x

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(x^2+5x-6)^0=1

(x^{2} + 5 x - 6)^{0} = 1

True for all x

Solution steps

(x^{2} + 5 x - 6)^{0} = 1

Apply rule

a^{0} = 1, a \neq = 0

1 = 1

Both sides are equal

True for all x

p, x = 1000 - 2 p

12 x - 20 - 5 x = 3 x + 32 - x

8 x - 3 = 5 x + 9

y, 2 x - 4 y = 3

2 x = \frac{2 π}{3}

What is the answer to (x^2+5x-6)^0=1 ?
The answer to (x^2+5x-6)^0=1 is True for all x
Solve for x: (x^2+5x-6)^0=1
The solution is True for all x