What are the solutions to the equation x^2-18x+58=0 ?

The solutions to the equation x^2-18x+58=0 are x=9+sqrt(23),x=9-sqrt(23)

Find the zeros of x^2-18x+58=0

The zeros of x^2-18x+58=0 are x=9+sqrt(23),x=9-sqrt(23)

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x^{2} - 18 x + 58 = 0

x = 9 + 23, x = 9 - 23

Decimal Notation

x = 13.79583 \dots, x = 4.20416 \dots

Solution steps

x^{2} - 18 x + 58 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 58}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 58 = 223

x_{1, 2} = \frac{- ( - 18 ) \pm 2 23}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 23}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 23}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 23}{2 \cdot 1} : 9 + 23

x = \frac{- ( - 18 ) - 2 23}{2 \cdot 1} : 9 - 23

The solutions to the quadratic equation are:

x = 9 + 23, x = 9 - 23

x y^{4} + x^{4}

8 g + 2 g - 11 = 9

5 q^{2} + 52 q + 20

\frac{( 3 x - 2 )}{5} \leq \frac{1}{2}

\frac{1}{1 - \frac{1}{1 - \frac{1}{a + 1}}}

What are the solutions to the equation x^2-18x+58=0 ?
The solutions to the equation x^2-18x+58=0 are x=9+sqrt(23),x=9-sqrt(23)
Find the zeros of x^2-18x+58=0
The zeros of x^2-18x+58=0 are x=9+sqrt(23),x=9-sqrt(23)