What is the answer to solvefor t,t(x)=(x^2-3x-18)/(x-8) ?

The answer to solvefor t,t(x)=(x^2-3x-18)/(x-8) is t=(x^2-3x-18)/(x(x-8));\quad x\ne 0

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solvefor t,t(x)=(x^2-3x-18)/(x-8)

solve for

t, t (x) = \frac{x ^{2} - 3 x - 18}{x - 8}

t = \frac{x ^{2} - 3 x - 18}{x ( x - 8 )}; x \neq = 0

Solution steps

t (x) = \frac{x ^{2} - 3 x - 18}{x - 8}

Divide both sides by

x; x \neq = 0

t = \frac{x ^{2} - 3 x - 18}{x ( x - 8 )}; x \neq = 0

\frac{5}{8} - \frac{2}{3} x = \frac{1}{6} x + 0.25

x - 3 = 1 + 7 x

\frac{x + 5}{6} = \frac{4 x + 8}{10}

- 8 x = - 48

- 8 x = - 24

What is the answer to solvefor t,t(x)=(x^2-3x-18)/(x-8) ?
The answer to solvefor t,t(x)=(x^2-3x-18)/(x-8) is t=(x^2-3x-18)/(x(x-8));\quad x\ne 0