What is the answer to (2x-1)/6-(2x+2)/4-1/5 ((x-2)/3)+1/5 =0 ?

The answer to (2x-1)/6-(2x+2)/4-1/5 ((x-2)/3)+1/5 =0 is x=-10/7

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(2x-1)/6-(2x+2)/4-1/5 ((x-2)/3)+1/5 =0

\frac{2 x - 1}{6} - \frac{2 x + 2}{4} - \frac{1}{5} (\frac{x - 2}{3}) + \frac{1}{5} = 0

x = - \frac{10}{7}

Decimal Notation

x = - 1.42857 \dots

Solution steps

\frac{2 x - 1}{6} - \frac{2 x + 2}{4} - \frac{1}{5} (\frac{x - 2}{3}) + \frac{1}{5} = 0

Multiply by LCM

10 (2 x - 1) - 30 (x + 1) - 4 (x - 2) + 12 = 0

Expand

10 (2 x - 1) - 30 (x + 1) - 4 (x - 2) + 12 : - 14 x - 20

- 14 x - 20 = 0

Move

20

to the right side

- 14 x = 20

Divide both sides by

- 14

x = - \frac{10}{7}

\frac{( 5 x + 6 )}{2} = - 4 x - 9

x, 3 x + 7 y = 0

x - 15 = 19

x - 15 = - 7

x, 2 x - 7 y = 12

What is the answer to (2x-1)/6-(2x+2)/4-1/5 ((x-2)/3)+1/5 =0 ?
The answer to (2x-1)/6-(2x+2)/4-1/5 ((x-2)/3)+1/5 =0 is x=-10/7
Solve for x: (2x-1)/6-(2x+2)/4-1/5 ((x-2)/3)+1/5 =0
The solution is x=-10/7