What is the answer to solvefor f,f= 1/(5+sqrt(x^2+y^2-1)) ?

The answer to solvefor f,f= 1/(5+sqrt(x^2+y^2-1)) is f=(5-sqrt(x^2+y^2-1))/(26-x^2-y^2)

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solvefor f,f= 1/(5+sqrt(x^2+y^2-1))

solve for

f, f = \frac{1}{5 + x ^{2} + y ^{2} - 1}

f = \frac{5 - x ^{2} + y ^{2} - 1}{26 - x ^{2} - y ^{2}}

Solution steps

f = \frac{1}{5 + x ^{2} + y ^{2} - 1}

Simplify

\frac{1}{5 + x ^{2} + y ^{2} - 1} : \frac{5 - x ^{2} + y ^{2} - 1}{26 - x ^{2} - y ^{2}}

f = \frac{5 - x ^{2} + y ^{2} - 1}{26 - x ^{2} - y ^{2}}

39 - 9 u = 4 u

r, A = P + PT

x, z = 5 x + y

- 1.3 = x - (- 13.2)

2 (0) - 4 y = 8

What is the answer to solvefor f,f= 1/(5+sqrt(x^2+y^2-1)) ?
The answer to solvefor f,f= 1/(5+sqrt(x^2+y^2-1)) is f=(5-sqrt(x^2+y^2-1))/(26-x^2-y^2)