What is the answer to x^2+5x+6=(x+2)(x+3) ?

The answer to x^2+5x+6=(x+2)(x+3) is True for all x

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x^2+5x+6=(x+2)(x+3)

x^{2} + 5 x + 6 = (x + 2) (x + 3)

True for all x

Solution steps

x^{2} + 5 x + 6 = (x + 2) (x + 3)

Expand

(x + 2) (x + 3) : x^{2} + 5 x + 6

x^{2} + 5 x + 6 = x^{2} + 5 x + 6

Move

6

to the right side

x^{2} + 5 x = x^{2} + 5 x

Subtract

x^{2} + 5 x

from both sides

x^{2} + 5 x - (x^{2} + 5 x) = x^{2} + 5 x - (x^{2} + 5 x)

Simplify

0 = 0

Both sides are equal

True for all x

5 - 2 y = 3

3 x + 3 = 3 x - 15

x, 4 x - y - 3 = 0

5 = x - 12

\frac{1}{2} (6 - z) = z

What is the answer to x^2+5x+6=(x+2)(x+3) ?
The answer to x^2+5x+6=(x+2)(x+3) is True for all x
Solve for x: x^2+5x+6=(x+2)(x+3)
The solution is True for all x