What is the answer to (x+4i)/i-(x+4i)/(2i)+x/(-4i)+x/4 =0 ?

The answer to (x+4i)/i-(x+4i)/(2i)+x/(-4i)+x/4 =0 is x=-4-4i

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(x+4i)/i-(x+4i)/(2i)+x/(-4i)+x/4 =0

\frac{x + 4 i}{i} - \frac{x + 4 i}{2 i} + \frac{x}{- 4 i} + \frac{x}{4} = 0

x = - 4 - 4 i

Solution steps

\frac{x + 4 i}{i} - \frac{x + 4 i}{2 i} + \frac{x}{- 4 i} + \frac{x}{4} = 0

Multiply by LCM

- 2 (x + 4 i) + x - i x = 0

Expand

- 2 (x + 4 i) + x - i x : - i x - x - 8 i

- i x - x - 8 i = 0

Move

8 i

to the right side

- i x - x = 8 i

Factor

- i x - x : - (i + 1) x

- (i + 1) x = 8 i

Divide both sides by

- i - 1

x = - 4 - 4 i

7 - 3 (x - 2) = (7 - x) 4 - 4 x

\frac{2 m - 1}{19} = \frac{m}{10}

8 x = - 14

7 - 2 b = 8 b + 37

\frac{3 x}{2} = - \frac{7}{2}

What is the answer to (x+4i)/i-(x+4i)/(2i)+x/(-4i)+x/4 =0 ?
The answer to (x+4i)/i-(x+4i)/(2i)+x/(-4i)+x/4 =0 is x=-4-4i