What is factor a^6+b^9 ?

The solution to factor a^6+b^9 is (a^2+b^3)(a^4-a^2b^3+b^6)

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factor a^6+b^9

factor

a^{6} + b^{9}

(a^{2} + b^{3}) (a^{4} - a^{2} b^{3} + b^{6})

Solution steps

a^{6} + b^{9}

Apply exponent rules

= (a^{2})^{3} + (b^{3})^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(a^{2})^{3} + (b^{3})^{3} = (a^{2} + b^{3}) ((a^{2})^{2} - a^{2} b^{3} + (b^{3})^{2})

= (a^{2} + b^{3}) ((a^{2})^{2} - a^{2} b^{3} + (b^{3})^{2})

Simplify

(a^{2})^{2} - a^{2} b^{3} + (b^{3})^{2} : a^{4} - a^{2} b^{3} + b^{6}

= (a^{2} + b^{3}) (a^{4} - a^{2} b^{3} + b^{6})

2 m - [(m - n) - (m + n)]

- \frac{1}{2}

ln (2 x^{2} - x) < 0

\frac{x ^{3} + 1}{x + 1} > 0

a^{3} - a

What is factor a^6+b^9 ?
The solution to factor a^6+b^9 is (a^2+b^3)(a^4-a^2b^3+b^6)