What is the answer to (x+1)/3+(x-6)/2 =(3x-1)/6 ?

The answer to (x+1)/3+(x-6)/2 =(3x-1)/6 is x= 15/2

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(x+1)/3+(x-6)/2 =(3x-1)/6

\frac{x + 1}{3} + \frac{x - 6}{2} = \frac{3 x - 1}{6}

x = \frac{15}{2}

Solution steps

\frac{x + 1}{3} + \frac{x - 6}{2} = \frac{3 x - 1}{6}

Multiply by LCM

2 (x + 1) + 3 (x - 6) = 3 x - 1

Expand

2 (x + 1) + 3 (x - 6) : 5 x - 16

5 x - 16 = 3 x - 1

Move

16

to the right side

5 x = 3 x + 15

Move

3 x

to the left side

2 x = 15

Divide both sides by

2

x = \frac{15}{2}

\frac{3}{5} x - 2 = \frac{2}{3} x + 3

\frac{1}{3} (r + 6) = \frac{1}{6} (r + 8)

0.9 (x - 20) = 830

A, A B = BC

f, f = {1 - x^{2}}

What is the answer to (x+1)/3+(x-6)/2 =(3x-1)/6 ?
The answer to (x+1)/3+(x-6)/2 =(3x-1)/6 is x= 15/2
Solve for x: (x+1)/3+(x-6)/2 =(3x-1)/6
The solution is x= 15/2