What is the answer to (3-x/2)-(1-x/3)=7-(x-x/2) ?

The answer to (3-x/2)-(1-x/3)=7-(x-x/2) is x=15

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(3-x/2)-(1-x/3)=7-(x-x/2)

(3 - \frac{x}{2}) - (1 - \frac{x}{3}) = 7 - (x - \frac{x}{2})

x = 15

Solution steps

(3 - \frac{x}{2}) - (1 - \frac{x}{3}) = 7 - (x - \frac{x}{2})

Move

(x - \frac{x}{2})

to the left side

\frac{x}{3} + 2 = 7

Move

2

to the right side

\frac{x}{3} = 5

Multiply both sides by

3

x = 15

\frac{x - b}{b} + \frac{x}{a} = \frac{1 - a}{a}

y, - 3 x + 2 y = 6

x, 2 x + 3 y + 6 = 0

\frac{1}{3} x + \frac{3}{4} - \frac{2}{3} = \frac{1}{2}

12 = 6 b

What is the answer to (3-x/2)-(1-x/3)=7-(x-x/2) ?
The answer to (3-x/2)-(1-x/3)=7-(x-x/2) is x=15
Solve for x: (3-x/2)-(1-x/3)=7-(x-x/2)
The solution is x=15