What is the answer to (3x-7}{11}=\frac{2x+9)/3 ?

The answer to (3x-7}{11}=\frac{2x+9)/3 is x=-120/13

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(3x-7}{11}=\frac{2x+9)/3

\frac{3 x - 7}{11} = \frac{2 x + 9}{3}

x = - \frac{120}{13}

Solution steps

\frac{3 x - 7}{11} = \frac{2 x + 9}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(3 x - 7) \cdot 3 = 11 (2 x + 9)

Expand

(3 x - 7) \cdot 3 : 9 x - 21

Expand

11 (2 x + 9) : 22 x + 99

9 x - 21 = 22 x + 99

Move

21

to the right side

9 x = 22 x + 120

Move

22 x

to the left side

- 13 x = 120

Divide both sides by

- 13

x = - \frac{120}{13}

24 - 3 m = 5 m

5 x - 3 = x - 12

6 x = 3 x - 6

\frac{x}{7} = 7

3 (2 x + 1) = 5 x - 3 + x

What is the answer to (3x-7}{11}=\frac{2x+9)/3 ?
The answer to (3x-7}{11}=\frac{2x+9)/3 is x=-120/13
Solve for x: (3x-7}{11}=\frac{2x+9)/3
The solution is x=-120/13