What is the answer to (x+2)(x+3)=(x-5)^2 ?

The answer to (x+2)(x+3)=(x-5)^2 is x= 19/15

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(x+2)(x+3)=(x-5)^2

(x + 2) (x + 3) = (x - 5)^{2}

x = \frac{19}{15}

Solution steps

(x + 2) (x + 3) = (x - 5)^{2}

Expand

(x + 2) (x + 3) : x^{2} + 5 x + 6

Expand

(x - 5)^{2} : x^{2} - 10 x + 25

x^{2} + 5 x + 6 = x^{2} - 10 x + 25

Move

6

to the right side

x^{2} + 5 x = x^{2} - 10 x + 19

Subtract

x^{2} - 10 x

from both sides

x^{2} + 5 x - (x^{2} - 10 x) = x^{2} - 10 x + 19 - (x^{2} - 10 x)

Simplify

15 x = 19

Divide both sides by

15

x = \frac{19}{15}

x, 5 x y - 12 = 2 y

11 x + 4 = 3 (1 - 2 x) + 1

x, 3 x - 5 y = - 13

x, 3 x - 5 y = - 11

3 (x + 5) - 10 = - 2 (x + 10)

What is the answer to (x+2)(x+3)=(x-5)^2 ?
The answer to (x+2)(x+3)=(x-5)^2 is x= 19/15
Solve for x: (x+2)(x+3)=(x-5)^2
The solution is x= 19/15