What is the answer to solvefor x,(x^4-y^4)=(x^2+y^2)(x+y)(x-y) ?

The answer to solvefor x,(x^4-y^4)=(x^2+y^2)(x+y)(x-y) is True for all x

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solvefor x,(x^4-y^4)=(x^2+y^2)(x+y)(x-y)

solve for

x, (x^{4} - y^{4}) = (x^{2} + y^{2}) (x + y) (x - y)

True for all x

Solution steps

(x^{4} - y^{4}) = (x^{2} + y^{2}) (x + y) (x - y)

x^{4} - y^{4} = (x^{2} + y^{2}) (x + y) (x - y)

Expand

(x + y) (x - y) : x^{2} - y^{2}

x^{4} - y^{4} = (x^{2} + y^{2}) (x^{2} - y^{2})

Expand

(x^{2} + y^{2}) (x^{2} - y^{2}) : x^{4} - y^{4}

x^{4} - y^{4} = x^{4} - y^{4}

Move

y^{4}

to the right side

x^{4} = x^{4}

Move

x^{4}

to the left side

0 = 0

Both sides are equal

True for all x

2 x - 16 = 0

5 x - 2 (2 x) = 3

2^{6064} = 4^{1010}

9 - 3 m = - 3

- 1 = \frac{5 + b}{- 10}

What is the answer to solvefor x,(x^4-y^4)=(x^2+y^2)(x+y)(x-y) ?
The answer to solvefor x,(x^4-y^4)=(x^2+y^2)(x+y)(x-y) is True for all x