What is the answer to h(2)=(2)^2-5(2)+7 ?

The answer to h(2)=(2)^2-5(2)+7 is h= 1/2

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h(2)=(2)^2-5(2)+7

h (2) = (2)^{2} - 5 (2) + 7

h = \frac{1}{2}

Decimal Notation

h = 0.5

Solution steps

h (2) = (2)^{2} - 5 (2) + 7

Simplify

2^{2} - 5 (2) + 7 : 1

h (2) = 1

Divide both sides by

2

h = \frac{1}{2}

x, - 5 x + 8 y = 0

- 14 = 3 + x

y, 2 y - 18 x = - 26

23 x - 19 x + 5 = 20

2 y + 6 = 4

What is the answer to h(2)=(2)^2-5(2)+7 ?
The answer to h(2)=(2)^2-5(2)+7 is h= 1/2
Solve for h: h(2)=(2)^2-5(2)+7
The solution is h= 1/2