What is factor 16x^2-40xy+25y^2 ?

The solution to factor 16x^2-40xy+25y^2 is (4x-5y)^2

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factor 16x^2-40xy+25y^2

factor

16 x^{2} - 40 x y + 25 y^{2}

(4 x - 5 y)^{2}

Solution steps

16 x^{2} - 40 x y + 25 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 x^{2} = (4 x)^{2}

25 y^{2} = (5 y)^{2}

- 40 x y = - 2 \cdot 4 x \cdot 5 y

= (4 x)^{2} - 2 \cdot 4 x \cdot 5 y + (5 y)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(4 x)^{2} - 2 \cdot 4 x \cdot 5 y + (5 y)^{2} = (4 x - 5 y)^{2}

= (4 x - 5 y)^{2}

10 x^{2} - 25 = 0

(\frac{4}{3})^{\frac{1}{2}} + (\frac{1}{3})^{- \frac{1}{2}}

1 - \frac{3}{3}

\frac{4}{6} + \frac{8}{6}

What is factor 16x^2-40xy+25y^2 ?
The solution to factor 16x^2-40xy+25y^2 is (4x-5y)^2