What is the answer to solvefor D, D/(F+2n^2)=q ?

The answer to solvefor D, D/(F+2n^2)=q is D=q(F+2n^2);\quad n\ne isqrt(F/2),n\ne-isqrt(F/2)

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solvefor D, D/(F+2n^2)=q

solve for

D, \frac{D}{F + 2 n ^{2}} = q

D = q (F + 2 n^{2}); n \neq = i \frac{F}{2}, n \neq = - i \frac{F}{2}

Solution steps

\frac{D}{F + 2 n ^{2}} = q

Multiply both sides by

F + 2 n^{2}

D = q (F + 2 n^{2}); n \neq = i \frac{F}{2}, n \neq = - i \frac{F}{2}

- 2 - 3 (2 x + 9) = - 32

\frac{3}{8} x + \frac{1}{6} x + \frac{5}{12} x = 69

- 2 (7 x) = - 28

\frac{4 x + 2}{3} - \frac{5 x - 7}{6} = \frac{3 - x}{2}

\frac{y - 2}{6} = - 2

What is the answer to solvefor D, D/(F+2n^2)=q ?
The answer to solvefor D, D/(F+2n^2)=q is D=q(F+2n^2);\quad n\ne isqrt(F/2),n\ne-isqrt(F/2)