What are the solutions to the equation 20p^2+33p+16=6 ?

The solutions to the equation 20p^2+33p+16=6 are p=-2/5 ,p=-5/4

Find the zeros of 20p^2+33p+16=6

The zeros of 20p^2+33p+16=6 are p=-2/5 ,p=-5/4

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20 p^{2} + 33 p + 16 = 6

p = - \frac{2}{5}, p = - \frac{5}{4}

Decimal Notation

p = - 0.4, p = - 1.25

Solution steps

20 p^{2} + 33 p + 16 = 6

Move

6

to the left side

20 p^{2} + 33 p + 10 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 33 \pm 3 3 ^{2} - 4 \cdot 20 \cdot 10}{2 \cdot 20}

3 3^{2} - 4 \cdot 20 \cdot 10 = 17

p_{1, 2} = \frac{- 33 \pm 17}{2 \cdot 20}

Separate the solutions

p_{1} = \frac{- 33 + 17}{2 \cdot 20}, p_{2} = \frac{- 33 - 17}{2 \cdot 20}

p = \frac{- 33 + 17}{2 \cdot 20} : - \frac{2}{5}

p = \frac{- 33 - 17}{2 \cdot 20} : - \frac{5}{4}

The solutions to the quadratic equation are:

p = - \frac{2}{5}, p = - \frac{5}{4}

\frac{2500}{\frac{500}{3}}

(\frac{( - 4 )}{9})^{2}

10 + x = - 9 x + 2

6 x^{2} - 6 x - 12

(4 x^{2})^{2}

What are the solutions to the equation 20p^2+33p+16=6 ?
The solutions to the equation 20p^2+33p+16=6 are p=-2/5 ,p=-5/4
Find the zeros of 20p^2+33p+16=6
The zeros of 20p^2+33p+16=6 are p=-2/5 ,p=-5/4