What is the answer to -(4-x)(x+3)=x^2-40 ?

The answer to -(4-x)(x+3)=x^2-40 is x=28

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-(4-x)(x+3)=x^2-40

- (4 - x) (x + 3) = x^{2} - 40

x = 28

Solution steps

- (4 - x) (x + 3) = x^{2} - 40

Expand

- (4 - x) (x + 3) : - x + x^{2} - 12

- x + x^{2} - 12 = x^{2} - 40

Move

12

to the right side

- x + x^{2} = x^{2} - 28

Move

x^{2}

to the left side

- x = - 28

Divide both sides by

- 1

x = 28

\frac{- 8 x - 1}{3} + 1.5 = - 9.5

x, 10 x + 5 y = 5

\frac{2}{3} (1 + x) = a

p, q = 200 - 2 p

\frac{3 x - 2}{5} - \frac{3 - 4 x}{2} = 2

What is the answer to -(4-x)(x+3)=x^2-40 ?
The answer to -(4-x)(x+3)=x^2-40 is x=28
Solve for x: -(4-x)(x+3)=x^2-40
The solution is x=28