What is the answer to n(n-2)(n+2)=n^3-4n ?

The answer to n(n-2)(n+2)=n^3-4n is True for all n

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n(n-2)(n+2)=n^3-4n

n (n - 2) (n + 2) = n^{3} - 4 n

True for all n

Solution steps

n (n - 2) (n + 2) = n^{3} - 4 n

Expand

(n - 2) (n + 2) : n^{2} - 4

n (n^{2} - 4) = n^{3} - 4 n

Expand

n (n^{2} - 4) : n^{3} - 4 n

n^{3} - 4 n = n^{3} - 4 n

Subtract

n^{3} - 4 n

from both sides

n^{3} - 4 n - (n^{3} - 4 n) = n^{3} - 4 n - (n^{3} - 4 n)

Simplify

0 = 0

Both sides are equal

True for all n

\frac{5 x}{3} + \frac{15}{2} = \frac{5}{2}

F = \frac{9}{5} c + 32, c

x + 5 = x - 5

a, a = (\frac{a + b}{2}) h

\frac{x}{3} - \frac{x}{5} = 3

What is the answer to n(n-2)(n+2)=n^3-4n ?
The answer to n(n-2)(n+2)=n^3-4n is True for all n
Solve for n: n(n-2)(n+2)=n^3-4n
The solution is True for all n