What is (3^{-2})/(b^{-4)} ?

The solution to (3^{-2})/(b^{-4)} is (b^4)/9

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simplify (3^{-2})/(b^{-4)}

simplify

\frac{3 ^{- 2}}{b ^{- 4}}

\frac{b ^{4}}{9}

Solution steps

\frac{3 ^{- 2}}{b ^{- 4}}

3^{- 2} = \frac{1}{9}

= \frac{\frac{1}{9}}{b ^{- 4}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{9 b ^{- 4}}

Simplify

9 b^{- 4} : \frac{9}{b ^{4}}

= \frac{1}{\frac{9}{b ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{4}}{9}

\frac{2}{6} \cdot \frac{1}{6}

0 = 6 t^{2} - 36 t + 30

4.8 = 0.4 q + 2.8

3^{\frac{1}{2}} \cdot 3^{\frac{3}{2}}

3^{3} \times 3^{3}