What is the answer to (m-x)/m-(n-x)/n =(2(m-n))/(mn) ?

The answer to (m-x)/m-(n-x)/n =(2(m-n))/(mn) is x=2;\quad mn\ne 0,m\ne n

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(m-x)/m-(n-x)/n =(2(m-n))/(mn)

\frac{m - x}{m} - \frac{n - x}{n} = \frac{2 ( m - n )}{mn}

x = 2; mn \neq = 0, m \neq = n

Solution steps

\frac{m - x}{m} - \frac{n - x}{n} = \frac{2 ( m - n )}{mn}

Multiply by LCM

n (m - x) - m (n - x) = 2 (m - n); mn \neq = 0

Expand

n (m - x) - m (n - x) : m x - n x

Expand

2 (m - n) : 2 m - 2 n

m x - n x = 2 m - 2 n; mn \neq = 0

Factor

m x - n x : x (m - n)

x (m - n) = 2 m - 2 n; mn \neq = 0

Divide both sides by

m - n; mn \neq = 0, m \neq = n

x = 2; mn \neq = 0, m \neq = n

y, 6 x - 3 y = - 6

x, 2 x + 7 y = 42

x, 2 x + 7 y = - 5

3 x = 2 x - 4

136 = - 8 (1 + 6 v)

What is the answer to (m-x)/m-(n-x)/n =(2(m-n))/(mn) ?
The answer to (m-x)/m-(n-x)/n =(2(m-n))/(mn) is x=2;\quad mn\ne 0,m\ne n