What is the answer to solvefor x,y-1= 2/3 (x-3) ?

The answer to solvefor x,y-1= 2/3 (x-3) is x=(3y-3)/2+3

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solvefor x,y-1= 2/3 (x-3)

solve for

x, y - 1 = \frac{2}{3} (x - 3)

x = \frac{3 y - 3}{2} + 3

Solution steps

y - 1 = \frac{2}{3} (x - 3)

Switch sides

\frac{2}{3} (x - 3) = y - 1

Multiply both sides by

3

2 (x - 3) = 3 y - 3

Divide both sides by

2

x - 3 = \frac{3 y - 3}{2}

Move

3

to the right side

x = \frac{3 y - 3}{2} + 3

6 x + 15 - 8 - 8 x = 7

91 = 9 U - 8

24 = x

4 (x + 5) + 4 = \frac{1}{2} (8 x + 48)

x, 10 x + 10 y = 0

What is the answer to solvefor x,y-1= 2/3 (x-3) ?
The answer to solvefor x,y-1= 2/3 (x-3) is x=(3y-3)/2+3