What is the answer to (k+2)/3 =(k-4)/5 ?

The answer to (k+2)/3 =(k-4)/5 is k=-11

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(k+2)/3 =(k-4)/5

\frac{k + 2}{3} = \frac{k - 4}{5}

k = - 11

Solution steps

\frac{k + 2}{3} = \frac{k - 4}{5}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(k + 2) \cdot 5 = 3 (k - 4)

Expand

(k + 2) \cdot 5 : 5 k + 10

Expand

3 (k - 4) : 3 k - 12

5 k + 10 = 3 k - 12

Move

10

to the right side

5 k = 3 k - 22

Move

3 k

to the left side

2 k = - 22

Divide both sides by

2

k = - 11

x, 2 x = 3 y - 6

8 x = 4 x - 8

5 (x - 6) = 2 (x + 3)

x, 4 x + y + 1 = 0

c, \frac{1}{4} c - 3 (\frac{1}{2} c + 3) = - \frac{3}{4} c

What is the answer to (k+2)/3 =(k-4)/5 ?
The answer to (k+2)/3 =(k-4)/5 is k=-11
Solve for k: (k+2)/3 =(k-4)/5
The solution is k=-11